-12x^2+25x+22=0

Solution for -12x^2+25x+22=0 equation:

-12x^2+25x+22=0

a = -12; b = 25; c = +22;
Δ = b2-4ac
Δ = 252-4·(-12)·22
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-41}{2*-12}=\frac{-66}{-24}
=2+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+41}{2*-12}=\frac{16}{-24}
=-2/3
$